Optimal. Leaf size=121 \[ -\frac {b}{4 e x^2}+\frac {b d}{e^2 x}-\frac {a+b \log (c x)}{2 e x^2}+\frac {d (a+b \log (c x))}{e^2 x}+\frac {d^2 (a+b \log (c x))^2}{2 b e^3}-\frac {d^2 (a+b \log (c x)) \log \left (1+\frac {d x}{e}\right )}{e^3}-\frac {b d^2 \text {Li}_2\left (-\frac {d x}{e}\right )}{e^3} \]
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Rubi [A]
time = 0.11, antiderivative size = 121, normalized size of antiderivative = 1.00, number of steps
used = 7, number of rules used = 7, integrand size = 21, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.333, Rules used = {269, 46, 2393,
2341, 2338, 2354, 2438} \begin {gather*} -\frac {b d^2 \text {PolyLog}\left (2,-\frac {d x}{e}\right )}{e^3}+\frac {d^2 (a+b \log (c x))^2}{2 b e^3}-\frac {d^2 \log \left (\frac {d x}{e}+1\right ) (a+b \log (c x))}{e^3}+\frac {d (a+b \log (c x))}{e^2 x}-\frac {a+b \log (c x)}{2 e x^2}+\frac {b d}{e^2 x}-\frac {b}{4 e x^2} \end {gather*}
Antiderivative was successfully verified.
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Rule 46
Rule 269
Rule 2338
Rule 2341
Rule 2354
Rule 2393
Rule 2438
Rubi steps
\begin {align*} \int \frac {a+b \log (c x)}{\left (d+\frac {e}{x}\right ) x^4} \, dx &=\int \left (\frac {a+b \log (c x)}{e x^3}-\frac {d (a+b \log (c x))}{e^2 x^2}+\frac {d^2 (a+b \log (c x))}{e^3 x}-\frac {d^3 (a+b \log (c x))}{e^3 (e+d x)}\right ) \, dx\\ &=\frac {d^2 \int \frac {a+b \log (c x)}{x} \, dx}{e^3}-\frac {d^3 \int \frac {a+b \log (c x)}{e+d x} \, dx}{e^3}-\frac {d \int \frac {a+b \log (c x)}{x^2} \, dx}{e^2}+\frac {\int \frac {a+b \log (c x)}{x^3} \, dx}{e}\\ &=-\frac {b}{4 e x^2}+\frac {b d}{e^2 x}-\frac {a+b \log (c x)}{2 e x^2}+\frac {d (a+b \log (c x))}{e^2 x}+\frac {d^2 (a+b \log (c x))^2}{2 b e^3}-\frac {d^2 (a+b \log (c x)) \log \left (1+\frac {d x}{e}\right )}{e^3}+\frac {\left (b d^2\right ) \int \frac {\log \left (1+\frac {d x}{e}\right )}{x} \, dx}{e^3}\\ &=-\frac {b}{4 e x^2}+\frac {b d}{e^2 x}-\frac {a+b \log (c x)}{2 e x^2}+\frac {d (a+b \log (c x))}{e^2 x}+\frac {d^2 (a+b \log (c x))^2}{2 b e^3}-\frac {d^2 (a+b \log (c x)) \log \left (1+\frac {d x}{e}\right )}{e^3}-\frac {b d^2 \text {Li}_2\left (-\frac {d x}{e}\right )}{e^3}\\ \end {align*}
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Mathematica [A]
time = 0.10, size = 110, normalized size = 0.91 \begin {gather*} -\frac {\frac {b e^2}{x^2}-\frac {4 b d e}{x}+\frac {2 e^2 (a+b \log (c x))}{x^2}-\frac {4 d e (a+b \log (c x))}{x}-\frac {2 d^2 (a+b \log (c x))^2}{b}+4 d^2 (a+b \log (c x)) \log \left (1+\frac {d x}{e}\right )+4 b d^2 \text {Li}_2\left (-\frac {d x}{e}\right )}{4 e^3} \end {gather*}
Antiderivative was successfully verified.
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Maple [A]
time = 0.08, size = 200, normalized size = 1.65
method | result | size |
risch | \(-\frac {a}{2 e \,x^{2}}+\frac {a \,d^{2} \ln \left (x \right )}{e^{3}}+\frac {a d}{e^{2} x}-\frac {a \,d^{2} \ln \left (d x +e \right )}{e^{3}}+\frac {b \ln \left (c x \right )^{2} d^{2}}{2 e^{3}}-\frac {b \ln \left (c x \right )}{2 e \,x^{2}}-\frac {b}{4 e \,x^{2}}+\frac {b d \ln \left (c x \right )}{e^{2} x}+\frac {b d}{e^{2} x}-\frac {b \,d^{2} \dilog \left (\frac {c d x +c e}{e c}\right )}{e^{3}}-\frac {b \,d^{2} \ln \left (c x \right ) \ln \left (\frac {c d x +c e}{e c}\right )}{e^{3}}\) | \(158\) |
derivativedivides | \(c^{3} \left (-\frac {a \,d^{2} \ln \left (c d x +c e \right )}{e^{3} c^{3}}-\frac {a}{2 e \,c^{3} x^{2}}+\frac {a \,d^{2} \ln \left (c x \right )}{e^{3} c^{3}}+\frac {a d}{e^{2} c^{3} x}-\frac {b \ln \left (c x \right )}{2 e \,c^{3} x^{2}}-\frac {b}{4 e \,c^{3} x^{2}}+\frac {b d \ln \left (c x \right )}{e^{2} c^{3} x}+\frac {b d}{e^{2} c^{3} x}-\frac {b \,d^{2} \dilog \left (\frac {c d x +c e}{e c}\right )}{e^{3} c^{3}}-\frac {b \,d^{2} \ln \left (c x \right ) \ln \left (\frac {c d x +c e}{e c}\right )}{e^{3} c^{3}}+\frac {b \ln \left (c x \right )^{2} d^{2}}{2 e^{3} c^{3}}\right )\) | \(200\) |
default | \(c^{3} \left (-\frac {a \,d^{2} \ln \left (c d x +c e \right )}{e^{3} c^{3}}-\frac {a}{2 e \,c^{3} x^{2}}+\frac {a \,d^{2} \ln \left (c x \right )}{e^{3} c^{3}}+\frac {a d}{e^{2} c^{3} x}-\frac {b \ln \left (c x \right )}{2 e \,c^{3} x^{2}}-\frac {b}{4 e \,c^{3} x^{2}}+\frac {b d \ln \left (c x \right )}{e^{2} c^{3} x}+\frac {b d}{e^{2} c^{3} x}-\frac {b \,d^{2} \dilog \left (\frac {c d x +c e}{e c}\right )}{e^{3} c^{3}}-\frac {b \,d^{2} \ln \left (c x \right ) \ln \left (\frac {c d x +c e}{e c}\right )}{e^{3} c^{3}}+\frac {b \ln \left (c x \right )^{2} d^{2}}{2 e^{3} c^{3}}\right )\) | \(200\) |
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [A]
time = 0.31, size = 141, normalized size = 1.17 \begin {gather*} -{\left (\log \left (d x e^{\left (-1\right )} + 1\right ) \log \left (x\right ) + {\rm Li}_2\left (-d x e^{\left (-1\right )}\right )\right )} b d^{2} e^{\left (-3\right )} - {\left (b d^{2} \log \left (c\right ) + a d^{2}\right )} e^{\left (-3\right )} \log \left (d x + e\right ) + \frac {{\left (2 \, b d^{2} x^{2} \log \left (x\right )^{2} + 4 \, {\left ({\left (d \log \left (c\right ) + d\right )} b + a d\right )} x e - {\left (b {\left (2 \, \log \left (c\right ) + 1\right )} + 2 \, a\right )} e^{2} + 2 \, {\left (2 \, b d x e + 2 \, {\left (b d^{2} \log \left (c\right ) + a d^{2}\right )} x^{2} - b e^{2}\right )} \log \left (x\right )\right )} e^{\left (-3\right )}}{4 \, x^{2}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {could not integrate} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] Timed out
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Timed out} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {could not integrate} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Mupad [F]
time = 0.00, size = -1, normalized size = -0.01 \begin {gather*} \int \frac {a+b\,\ln \left (c\,x\right )}{x^4\,\left (d+\frac {e}{x}\right )} \,d x \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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